dim函數(shù)的第三個參數(shù)，也就是截取字符的長度，我在設置這個的時候，出了些問題,提示無效的過程調用或參數(shù),本文詳細介紹如何解決

dim函數(shù)的第三個參數(shù)，也就是截取字符的長度，我在設置這個的時候，出了些問題:response.write mid(up_address,a(i),a(i+1)-1) & “<br />”像我上面這樣寫的時候，它就會報錯，提示無效的過程調用或參數(shù),

response.write mid(up_address,a(i),a(i+1)+1) & “<br />”但是當我把其中的a(i+1)-1改為a(i+1)+1時，就能執(zhí)行了,a(i+1)對應的值是11，可為什么只能減不能加呢?全部代碼如下:

VB code:

代碼如下:

dim a(),up_address

up_address = "aaa djaldk adflj adafadfasdfa afd ad"

redim a(len(up_address))

a(0) = instr(up_address," ")

response.write a(0) & "<br />"

if a(0)<>0 then

for i=0 to len(up_address)-1

a(i+1) = instr(a(i)+1,up_address," ")

response.write mid(up_address,a(i),a(i+1)-1) & "<br />"

if a(i+1)=0 then

exit for

end if

response.write a(i+1) & "<br />"

next

end if如上代碼，我是想把字符串按空格分解出來，但是mid的第三個參數(shù)那出了點問題，我本來是想這樣截取的：

VB code：

代碼如下:

mid(up_address,a(i),a(i+1)-a(i)-1)

‘a(i)是空格的位置

‘a(i+1)是下一個空格的位置

‘a(i+1)-a(i)-1是兩個空格直間的字符長度

現(xiàn)在的問題是，經測試，mid的第三個參數(shù)那，無法使用減法，也就是說，我可以寫a(i+1)+，但不能寫a(i+1)-，想了好久，我一直不明白問題出在哪？應該怎么來解決呢？

出現(xiàn)這個問題是因為上面的MID函數(shù)的第三個參數(shù)出現(xiàn)了負數(shù),下面是在網上找的測試的VBS代碼，原理一樣，如下的代碼：

VBScript code:

代碼如下:

dim a(),up_address

up_address = "aaa djaldk adflj adafadfasdfa afd ad"

MsgBox len(up_address) '36

redim a(len(up_address)) 'a(36)

a(0) = instr(up_address," ")

MsgBox a(0) 'a(0)=4

MsgBox a(0) & "<br />"

if a(0)<>0 then

for i=0 to len(up_address)-1

a(i+1) = instr(a(i)+1,up_address," ")

MsgBox a(i) &" "& (a(i+1)-1)‘這里的結果為34，-1，所以導致出錯

MsgBox mid(up_address,a(i),a(i+1)-1) & "<br />"

if a(i+1)=0 then

exit for

end if

MsgBox a(i+1) & "<br />"

next

end if